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solid mensuration

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A circle has an area equal to 25 pi sq.cm. Its diameter AB coincides with one of the sides of triangle ACB in which the vertex C lies on the circle. If the triangle has an area equal to 11 sq.cm, find its perimeter.

Please include solution. Thanks.

  • solid mensuration -

    The circle radius is 5 cm. That comes from the area.
    The triangle ACB is a right triangle with AB as a diameter. The length of AB is 10 cm, since it is a diameter
    (AC)^2 + (BC)^2 = (AB)^2 = 100
    Area = (1/2)(AB)*(BC) = 11
    (AC)*(BC) = 22
    (BC)=22/(AC)
    (AC)^2 + 484/(AC)^2 = 100
    Solve for AC. The short side is about 2.3. Then get BC and the perimenter.
    Then get BC

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