Post a New Question


posted by .

CaCO3 + 2 HCl -> CaCl2 + CO2 + H2O

Calculate the molarity of hydrochloric acid solution if an initial mass of 4.568g of CaCO3 was reacted with 25.0mL of the acid and 2.678g of CaCO3 remain after the reaction is complete.

  • chemistry -

    g CaCO3 reacted = 4.568 g - 2.678g = ?g CaCO3 used in the titration.
    mols CaCO3 = gCaCO3 used/molar mass =?
    mols HCl = twice that (from the balanced equation coefficients)
    M HCl = mols HCl/L HCl.

  • chemistry -

    1.890CaCO3/1 x 1mole CaCO3/100.09 x2molesHCl/1mole CaCO3 x1/0.025

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question