posted by Josh .
A propane stove burned 470. grams of propane and produced 625 milliliters of
water. What is the % yield?
C₃H₈+5O₂ -> 3CO₂+ 4H₂O
mols C3H8 = 470/molar mass C3H8.
Using the coefficients in the balanced equation, convert mols 3H8 to mols H2O
Now convert mols H2O to grams H2O. g = mols x molar mass. This is the theoretical yield (TY) in grams. The actual yield (AY) is 625 mL so we must convert that to grams. I assume you are expected to use 625 mL x (1 mol/22,400) = about 0.028 mols and g = mols x molar mass = 0.028 x 18 = about 0.5g.
Then %yield = (AY/TY)*100 = ?