ind the derivative of y= (2x^2+1)/(x-3)
if y = u/v, y' = (u'v - uv')/v^2
so,
y' = ((4x)(x-3) - (2x^2+1)(1)]/)x-3)^2
= (4x^2-12x - 2x^2 - 1)/(x-3)^2
= (2x^2 - 12x - 1)/(x-3)^2
so,
y' = ((4x)(x-3) - (2x^2+1)(1)]/)x-3)^2
= (4x^2-12x - 2x^2 - 1)/(x-3)^2
= (2x^2 - 12x - 1)/(x-3)^2