# calculus

posted by .

What is the value of this limit?

lim (x^2+4/^2-3x+1)
x->4

A. 1
B. 4
C. 5
D -oo
E. oo

• calculus -

***x^2-3x+1

• calculus -

is this

lim (x^2 + 4)/(x^2 - 3x + 1)
x ---> 4

the first step in any limit is to actually sub in the approach value
in this case we get

lim(16+4)/(16 - 12 + 1)
= 20/5
= 4 , which is a real number, so we have no problem with this limit

the answer is 4 , all done!

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