What length of pendulum has a period of 0.9 s on Earth?
T^2 = 4*(pi)^2(L/g).
T^2 = 4*(3.14)^2(L/g) = (0.9)^2
39.48(L/g) = 0.81
L/g = 0.02052
L = 0.02052*9.8 = 0.20 m.
T^2 = 4*(3.14)^2(L/g) = (0.9)^2
39.48(L/g) = 0.81
L/g = 0.02052
L = 0.02052*9.8 = 0.20 m.