posted by Kacie .
a sodium hydroxide solution was prepared according to the procedure outlined in this weeks experiment. This sodium hydroxide solution was standardized by by titration against exactly 10mL of a 0.28M hydrochloric acid solution. In three titrations, the volumes of the sodium hydroxide solution required to reach the equivalence point where 8.03 mL, 8.18mL, and 7.94mL. What is the molarity of your sodium hydroxide solution
NaOH + HCl ==> NaCl + H2O
mols HCl = M x L = ?
mols NaOH = mols HCl (Look at the coefficients in the balanced equation.)
Then M NaOH = molos NaOH/L NaOH.
You may calculate the three values for the three different volumes, then average the three M values OR you may average the three volumes initially and make one calculation.