posted by .

I don't understand what to do after i convert everything into cos and sin.


  • trig -

    what you want to do is to show that using standard identities and algebraic manipulation, the left side can be made equal to the right side.


    change to sin,cos using trig identities
    cosx(sinx/cosx + cosx/sinx)

    now do some algebra
    cosx*sinx/cosx + cosx*cosx/sinx
    sinx + cos^2(x)/sinx
    sinx*sinx/sinx + cos^2(x)/sinx
    (sin^2(x) + cos^2(x))/sinx

    now apply standard trig identities


Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Pre-Calc

    How do I solve this? My work has led me to a dead end. tan(45-x) + cot(45-x) =4 my work: (tan45 - tanx)/(1+ tan45tanx) + (cot45 - cotx)/(1 + cot45cotx) = 4 (1-tanx)/(1+tanx) + (1-cotx)/(1+cotx) = 4 Then I found a common denominator,
  2. trig

    express this in sinx (1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?
  3. Trigonometry.

    ( tanx/1-cotx )+ (cotx/1-tanx)= (1+secxcscx) Good one! Generally these are done by changing everything to sines and cosines, unless you see some obvious identities. Also generally, it is best to start with the more complicated side …
  4. trig

    it says to verify the following identity, working only on one side: cotx+tanx=cscx*secx Work the left side. cot x + tan x = cos x/sin x + sin x/cos x = (cos^2 x +sin^2x)/(sin x cos x) = 1/(sin x cos x) = 1/sin x * 1/cos x You're almost …
  5. drwls

    My previous question: Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) = (sinx/cosx)*cotx*(1/sinx) "The last steps should be obvious" Not to me. I can convert (sinx/cosx) to …
  6. trig

    verify the identity: tan^2x(1+cot^2x)=1/1-sin^2x Verify the Id: tanx + cotx/ tanx-cotx = (1/sin^2x-cos^2x)
  7. trig

    verify the identity (tanx+cotx) (1) __________ = ______________ (tanx-cotx) (sin^2x-cos^2x)
  8. trig

    We are doing trig identities in school. I need help with these five: 1.1+sinx/1-sinx=cscx+1/cscx-1 2.tanx+sinx/1+cosx=tanx 3.sec^2x/sin^2x=1/sin^2x+1/cos^2x 4.tan^2x/1+tan^2x=1-cos^2x 5.sinx-sin^3x/cos^3x=tanx
  9. trig

    Verify the trigonometric identity. Please show all steps. tanx-cotx/tanx+cotx=sin^2x-cos^2x
  10. Precalculus/Trig

    I can't seem to prove these trig identities and would really appreciate help: 1. cosx + 1/sin^3x = cscx/1 - cosx I changed the 1: cosx/sin^3x + sin^3x/sin^3x = cscx/1-cosx Simplified: cosx + sin^3x/sin^3x = cscx/1-cosx I don't know …

More Similar Questions