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The pilot of an airplane traveling 250km/h wants to drop supplies to flood victims isolated on a patch of land 190m below.

how long to drop 190 m?
190 = (1/2) (9.81)t^2
t = 6.22 seconds
how far horizontal in 6.22 s ?
(250,000 m/3600 s)6.22 s = 432 meters
so drop 432 meters before reaching target zenith

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