precalculus

posted by .

Find the first five terms of the given recursively defined sequence.
an = 3an − 1 + 9 and a1 = 2

  • precalculus -

    If yourexpression mean :

    an = 3 a ( n − 1 ) + 9

    a1 = 2

    then

    a2 = 3 a1 + 9 = 3 * 2 + 9 = 6 + 9 = 15

    a3 = 3 a2 + 9 = 3 * 15 + 9 = 45 + 9 = 54

    a4 = 3 a3 + 9 = 3 * 54 + 9 = 162 + 9 = 171

    a5 = 3 a4 + 9 = 3 * 171 + 9 = 513 + 9 = 522

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Math

    Find the first five terms of the sequence for which a1=5,and an+1=3an+1. an+1=3an+1 a1+1=3a1+1 a2=3(5)+1 a2=16 a2+1=3a2+1 a3=3(16)+1 a3=49 a3+1=3a3+1 a4=3(49)+1 a4=148 a4+1=3a4+1 a5=3(148)+1 a5=445 so the first five terms are: 5,16,49,148,445
  2. calculus

    A) How do you prove that if 0(<or=)x(<or=)10, then 0(<or=)sqrt(x+1)(<or=)10?
  3. Calculus

    A) How do you prove that if 0(<or=)x(<or=)10, then 0(<or=)sqrt(x+1)(<or=)10?
  4. calculus

    A) How do you prove that if 0(<or=)x(<or=)10, then 0(<or=)sqrt(x+1)(<or=)10?
  5. Discrete Math

    Calculate R(4) where the recursively defined sequence R is given by: R(1) = 2, R(2) = 3, and, R(n) = R(n − 1) + 2R(n − 2) + n, n > 2
  6. algebra 2

    A sequence is defined recursively by a1=1,an=(an-1+1)^2. Write the first 4 terms of the sequence.
  7. Urgent math

    Find the first five terms of the given recursively defined sequence. an = 3an − 1 + 6 and a1 = 1 a1= a2= a3= a4= a5=
  8. Math

    this is a difficult question for me please help! thankyou A sequence is defined recursively by an + 1 = 3an − n, a1 = 2. Find the first six terms of the sequence. a1 = a2 = a3 = a4 = a5 = a6 =
  9. math asap

    this is a difficult question for me please help! thankyou A sequence is defined recursively by an + 1 = 3an − n, a1 = 2. Find the first six terms of the sequence. a1 = a2 = a3 = a4 = a5 = a6 =
  10. math

    Write the first five terms of the sequence defined recursively. Use the pattern to write the nth term of the sequence as a function of n. (Assume that n begins with 1.) a (subtext) 1 =4,a (subtext) (k+1) =−a (subtext) k a. a …

More Similar Questions