Algebra
posted by Lauryn .
expand log2 (8x^2+48X+72)

Log2(8x^2+48x+72).
Log2(8)(x^2+6x+9) =
Log2(8)(x+3)^2 =
Log2(8)+2Log2(x+3) =
3 + 2Log2(x+3).
Respond to this Question
Similar Questions

Algebra 2
solve log2(3x1)log2(x1)=log2(x+1) i have absolutely no idea how to solve this. can anyone help me, please? 
Logarithms
I'm working on logarithmic equations and I'm stuck on how my book arrives at the next step. First, they use the change of base formula on, log(sqrt(2))(x^3  2) (sqrt(2)) is the base,changing to base 2 log(sqrt(2))(x^3  2)= log2(x^3 … 
algebra
(48x^6)/(48x^6/12x^212y^2)/(4x^5)/(3xy+3y^2) 
Algebra
Find the product: 6x(8x^2+x+5) A)14x^35x^2x B)48x^3+x+5 C)48x^36x^230x D)48x^26x30 
math
solve the equation log2(x+4)log4x=2 the 2 and 4 are lower than the g This is what I got: log2(x+4)+log2(4^x)=2 log2((x+4)*4^x)=2 4^x(x+4)=4 x=0 is a solution? 
Math
Hello! Could someone please take a look at the problem below and let me know if I made mistakes in simplifying the given equation? 
Math
I don't understand how log2 √(1/2) turned into log2 2^(1/2). Quote: You will have to know the 3 prime properties of logs 1. logk (AB) = logk A + logk B 2. logk(A/B) = logk A  logk B 3. logk (A^n) = n logk A where k is any positive … 
Math
I don't understand how log2 √(1/2) turned into log2 2^(1/2). Quote: You will have to know the 3 prime properties of logs 1. logk (AB) = logk A + logk B 2. logk(A/B) = logk A  logk B 3. logk (A^n) = n logk A where k is any positive … 
Math
I don't understand how log2 √(1/2) turned into log2 2^(1/2). Quote: You will have to know the 3 prime properties of logs 1. logk (AB) = logk A + logk B 2. logk(A/B) = logk A  logk B 3. logk (A^n) = n logk A where k is any positive … 
Urgent math
i need help with these two homework problems Use the Laws of Logarithms to combine the expression into a single logarithm log2 5 − 5 log2 x + 1/2 log2(x + 1) Solve the logarithmic equation for x log2(x + 2) + log2(x − 1) …