Maths (Linear and Quadratic Equations)
posted by Saud .
I need to solve a pair of equations where one is linear and the other is quadratic.
2x2 + 3xy + y2 = 0
3x + y = 2
last 2 in 2x2 is square root two, same after y2.
help please!!!!!!!!!!!!!!!

just substitute the linear into the quadratic:
y = 23x
2x^2 + 3x(23x) + (23x)^2 = 0
2x^2 + 6x  9x^2 + 4  12x + 9x^2 = 0
2x^2  6x + 4 = 0
2(x1)(x2) = 0
solutions: (1,1)(2,4)
or,
2x^2 + 3xy + y^2 = 0
(2x+y)(x+y) = 0
y = 2x or y = x
3x+(2x) = 2
x = 2, so y = 4
3x+(x) = 2
x = 1, so y = 1