precalculus
posted by marcus .
e^3x7 x e^2x =4e
First step I get e^1x7 =4e
For the example in my book, the next step they divided by e. But I have no idea how to do this, or what involves?

You have to apply the indices rule: a^m /a^n= a^(mn)
so e^(x7)/e^1= e^(x8). We then get: e^(x8)=4 Use ln: x8= ln4 so x=8+ln4
OK?
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