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math

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for n repeated independent trials, with constant probability of success p for all trials, find the probability of exactly x succes n=5,p=1/3, x=4

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    If there are only two possible outcomes from each trial then it's a binomial and by using the formula nCx p^x(1-p)^(n-x) we get; 5C4(1/3)^4(2/3)^1=0.04115

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