posted by Rebekah .
how do you find x in 7-=log(x/10^-12)
I will assume that -= is a typo and should be just =
7 = log(x/10^-12)
7 = logx - log 10^-12
7 = logx - (-12)
-5 = logx
x = 10^-5
the thing is its / instead of - so I thought that I multiply each side by 10^-12 but im not sure
you cannot multiply by 10^12 because that is inside the log.
suppose you had 2 = √(x/4)
You can't multiply by 4, giving
8 = √x
because that would be trying to slide a value through the "walls" of the function calculation