Physics

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A sled is pulled across a horizontal snow surface with a constant velocity. The force being applied is 80 N at an angle of 53 degrees to the ground. What is the magnitude of the force of friction of the snow acting on the sled?

  • Physics -

    ANGLE=ang

    ang<80>/f(x>(l/2)(ff)(mg)
    <260>(1.333%)(3.7)
    %=fn/viv<0.16/.409n)
    [pi^2](fn(80))

    ANS: 41.19

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