How many milliliters of a 0.25 M sucrose solution contain 2.0 grams? The molar mass of sucrose (C12H22O11 ) is 342.3 g/mol.
To find the volume of a given mass in a solution, we can use the formula:
Volume (in mL) = Mass (in grams) / Concentration (in mol/L) / Molar mass (in g/mol) * 1000
Let's substitute the given values into the formula:
Mass = 2.0 grams
Concentration = 0.25 M
Molar mass = 342.3 g/mol
Volume = 2.0 g / 0.25 M / 342.3 g/mol * 1000
Now, let's calculate the volume:
Volume = 2.0 / 0.25 / 342.3 * 1000 = 23.24 mL
Therefore, 2.0 grams of the 0.25 M sucrose solution contain approximately 23.24 milliliters.
To find the number of milliliters of a 0.25 M sucrose solution that contain 2.0 grams, we can follow these steps:
Step 1: Convert grams of sucrose (C12H22O11) to moles.
- Use the molar mass of sucrose (342.3 g/mol) to convert grams to moles.
2.0 g C12H22O11 * (1 mol C12H22O11 / 342.3 g C12H22O11) = 0.0058 mol C12H22O11
Step 2: Use the molarity (0.25 M) to find the volume in liters (L).
- Molarity is defined as moles of solute per liter of solution.
Volume (L) = Moles / Molarity
Volume (L) = 0.0058 mol C12H22O11 / 0.25 mol/L = 0.0232 L
Step 3: Convert liters to milliliters.
- There are 1000 milliliters (mL) in 1 liter.
Volume (mL) = Volume (L) * 1000 mL/L = 0.0232 L * 1000 mL/L = 23.2 mL
Therefore, 2.0 grams of a 0.25 M sucrose solution contains 23.2 milliliters.
mols = grams/molar mass
Solve for mols.
M = mols/L. Solve for L and convert to mL.