trigonometry
posted by Maria .
Been trying this forever so it says: Simplify 1+sin2x+cos2x/1+sin2xcos2x
ive tried this problem so many times I need help with it...

I believe you mean
(1+sin2x + cos2x)/(1+sin2x  cos2x)
= (sin^2 x + cos^2 x + 2sinxcosx + cos^2 x  sin^2x)/(sin^2 x + cos^2 x + 2sinxcosx  cos^2x + sin^2x)
= (2cos^2 x + 2sinxcosx)/(2sin^2 x + 2sinxcosx)
= 2cosx(cosx+sinx)/((2sinx(sinx+cos))
= 2cosx/2sinx
= cot x
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