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You throw a ball downward from a window at a speed of 2.0m/s. The ball accelerates at 9.8m/s^2. How fast is it moving when it hits the sidewalk 2.5m below?

  • physics -

    initial speed: 2 m/s
    a: -9.8 m/s^2
    s: -2.5 m
    final speed: ?
    Vf^2 - Vi^2 = 2as

    v^2 - 2^2 = 2•-9.8•-2.5

    v^2-4 = 49

    v^2 = 53
    final speed is approx. 7.28

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