posted by jason .
An outfielder throws a 1.88 kg baseball at a
speed of 57 m/s and an initial angle of 10.2.
What is the kinetic energy of the ball at the
highest point of its motion?
Answer in units of J
To find the KE of the ball at the highest ball of motion, we have to use the initial velocity and angle to find the horizontal velocity.
V(horizontal) = V(initial) * cos(theta)
V(horizontal) = (57 m/s) * cos(10.2)
V(horizontal) = 56.099 m/s
Using the velocity in the horizontal direction that we found, along with the mass given, we can calculate the KE of the ball at its highest point.
KE = (1/2)mv^2
KE = (1/2)(1.88 kg)(56.099 m/s)^2
KE = 2958.27 J