calculus

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find the area of the largest rectangle having one side on the x axis and inscribed in the triangle formed by the lines y=x, y=0, and 3x + y = 20

  • calculus -

    if the height of the rectangle is y, the base of the rectangle is (20-y)/3 - y.

    So, the area is y((20-y)/3 - y) = 4/3 (5y-y^2)

    max area where 5-2y = 0, or y = 5/2.

    So, the largest rectangle has area 50/3

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