When archer pulls an arrow back in his bow.He is storing potential energy in his bow What avg force must the archer exert if he pulls the string back a distance of 30 cm?

To calculate the average force exerted by the archer when pulling the string back, we can use the concept of potential energy. The potential energy stored in the bow is given by the formula:

Potential Energy = (1/2) * k * x^2,

where k is the spring constant of the bow and x is the distance the string is pulled back.

In this case, we are given that the distance the string is pulled back, x, is 30 cm (or 0.30 m). However, we need the spring constant, k, to calculate the potential energy.

To find the spring constant, you would need to know specific information about the bow, such as its stiffness or a force-displacement graph. Unfortunately, without this information, it is not possible to determine the average force exerted by the archer.

However, in general, the average force exerted by the archer can be calculated by dividing the change in potential energy by the distance over which the force is exerted. In this case, the change in potential energy would be the potential energy stored when the string is pulled back to a distance of 30 cm, minus the potential energy when the string is at rest.

I apologize for not being able to provide a specific answer, but I hope this explanation helps you understand the concept of potential energy and how it relates to determining the average force exerted by the archer.