# Precalc/Triangles

posted by .

Draw and solve any triangles satisfying
alpha = 29 degrees
a = 7
c = 14

I realize I need to draw a non-right triangle and label the sides but I am completely confused one what to do after I draw the triangle

• Precalc/Triangles -

Unless you were told to do so, why must it be right-angled

e.g. triangle ABC , were a=7, c=14 and angle A = 29°
(assuming you are using the convention of labeling the vertices with captital letters and the sides opposite with small letters

by Sine Law
SinC/14 = sin29/7
sinC = 14sin29/7 = .96961..
angle C = 75.8°
then angle B = 180-29-75.8 = 75.2°

and once again:
b/sinB = a/sinA
b/sin75.2 = 7/sin29
b = 13.96

(notice the triangle is "almost" isosceles)

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