posted by Emma .
A 5ml, 10ml, 15 ml, and 20ml Aliquot of 0.010 M sodium salicylate solution was diluted to 100 ml in four different 100ml volumetric flasks with the iron (III)Chloride solution. What are their concentrations.
You diluted the first one from 5 mL to 100 mL; therefore, the new concn will be = 0.01 M x (5 mL/100 mL) = ?M
Or you can say you diluted it by a factory of 100/5 = 20 times; therefore, it is 1/20th as strong.
Then 0.01 x 1/20 = ?
Thankyou Dr. Bob also on my other question I am not sure how to get the heat capacity of NH4Cl to calculate molar enthalpy and I also don't know how to determine the concentration of NH4Cl inside the calorimeter. Please help me on that question as well and thankyou soo much.