# math

posted by .

f(x)=x^4-4x^3+10

Find the inflection point(s), if there are any.

• math -

f'' = 12x^2 - 24x = 12x(x-2)

looks like inflections at x=0 and 2

## Similar Questions

1. ### Pre-calculus

Find the critical point of the function y=-2(x-1)^2-3. Then, determine whether the point represents a maximum, a minimum, or a point of inflection.
2. ### Pre-calculus

Find the critical point of the function y=-2(x-1)^2-3. Then, determine whether the point represents a maximum, a minimum, or a point of inflection.
3. ### calculus

Find all relative extrema and points of inflection of the function: f(x) = sin (x/2) 0 =< x =< 4pi =< is supposed to be less than or equal to. I can find the extrema, but the points of inflection has me stumped. The inflection …
4. ### Math

Assume k is a constant. the function g(x)= x4- 6k(x2) + 6k2 + x has at least one point of inflection a- if and only if k>0 b- if and only if k >= 0 My answer: g'(x) = 4x3 - 12kx + 6k2 g''(x) = 12x2 - 12k = 12(x2 - k) k has to …
5. ### Calculus

The number of people who donated to a certain organization between 1975 and 1992 can be modeled by the equation D(t)=-10.61t^(3)+208.808t^(2)-168.202t+9775.234 donors, where t is the number of years after 1975. Find the inflection …
6. ### calculus ..>steve

Given a function f(x)2/3x^3+5/2x^2-3x. a) Find i. The inflection point. ii. The y-intercept and x-intercept. b) Sketch the graph of f(x). i have already try it..but i don't understand.. which graph that is true.. the first or second …
7. ### Calculus

f(x)= x/(1+x)^2 c) find the intervals of concavity and the inflection points. My answers: f is concave downward on (- infinity, 2) and concave upward on (2, infinity). Inflection point: ( 2, 2/9)
8. ### Calculus

If f(x) is a continuous function with f"(x)=-5x^2(2x-1)^2(3x+1)^3 , find the set of values for x for which f(x) has an inflection point. A. {0,-1/3,1/2} B. {-1/3,1/2} C. {-1/3} D. {1/2} E. No inflection points
9. ### Calculus AB

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 3x(1/3) + 6x(4/3). You must justify your answer using an analysis of f '(x) and f "(x). My start to a solution: x-values: (-1/8) and (-1/4) …
10. ### Math Calc

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 3x(1/3) + 6x(4/3). You must justify your answer using an analysis of f '(x) and f "(x) I got -1/8 for a minimum point and 1/4 for inflection …

More Similar Questions