chemistry

posted by .

How many moles are in 1.50 x 1023 molecules NH3?
A. 2.49 x 10 -1 mol NH3
B. 2.49 x 101 mol NH3
C. 2.65 x 10 -1 mol NH3
D. 2.78 x 10 1 mol NH3

maybe B

  • chemistry -

    I don't think so. There are 6.02E23 things in a mole of things.

  • chemistry -

    yes.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. chemistry

    from the balanced equation 4NH3 +7O2 - 4NO2 + 6H2O How many molecules of water are produced when 2.25 moles of ammonia are completely reacted?
  2. Chemistry

    srry I placed the question in the wrong spot. The equation is 2NH3 <=> N2 + 3H2 1 mole of NH3 injected intoa 1L flask 0.3 moles of H2 was found the concentration of N2 at equlibrium is 0.1M how do I find the concentration of …
  3. Honors Chemistry

    "How many grams of NH3 can be produced from the reaction of 28 g of N2 and 25 g of H2?
  4. Chemistry

    Could someone please check my answers/work for the following questions. EQUATION: 3H2+N2 -->2NH3 1) How many grams of NH3 can be produced from 3.98 mol of N2?
  5. college chem

    The cation M2+ reacts with NH3 to form a series of complex ions as follows: M2+ + NH3 M(NH3)2+ K1 = 102 M(NH3)2+ + NH3 M(NH3)2 2+ K2 = 103 M(NH3)2 2+ + NH3 M(NH3)3 2+ K3 = 102 A 1.0 × 10–3 mol sample of M(NO3)2 is added to 1.0 L …
  6. chemistry

    what is the Molarity (M) of a 0.87m aqueous solution of ammonia, NH3?
  7. College Chemistry

    In a reaction vessel, the following reaction was carried out using 0.250 mol of NH3(l) and 0.100 mol of N2(g). 4NH3(l) + N2(g) ¡ú 3N2H4(l) Which of the following represents the composition in moles in the vessel when the reaction …
  8. Chemistry

    How many moles are in 1.50 x 1023 molecules NH3?
  9. chem

    Calculate the equilibrium concentration of NH3,Cu^2+,[ Cu(NH3)]^2+ ,[Cu(NH3)2]^2+,[Cu(NH3)3]^2+,and[Cu(NH3)4]^2+ in a solution made by mixing 500.0 ml of 3.00 M NH3 with 500.0 ml of 2.00*10^-3 M Cu(NO3)2. The sequential equilibria …
  10. Chemistry

    Determine the number of moles of N2 that are required to produce 12 mol of NH3 using the equation, N2 + 3H2 --> 2NH3. 12 mol NH3 x 1 mol N2/2 mol NH3 = 6 moles of N2.

More Similar Questions