A hydraulic lift is used to jack a 780 kg car 15 cm off the floor. The diameter of the output piston is 15 cm, and the input force is 160 N.

a)What is the area of the input piston (in m^2)?
b)What is the work done in lifting the car 15 cm?
c)If the input piston moves 13 cm in each stroke, how high does the car move up for each stroke?
d)How many strokes are required to jack the car up 15 cm?

a) diameter = 2*radius = 0.15 m;

radius = 0.15/2

area = pi*radius^2

b)Work = Force*distance = 160*0.15

a) To find the area of the input piston, you can use the formula for the area of a circle, which is given by A = πr², where A is the area and r is the radius of the circle.

In this case, the diameter of the input piston is given as 15 cm. The radius of the input piston is half of the diameter, so the radius (r) can be calculated as 15 cm / 2 = 7.5 cm.

Now, to convert the radius from centimeters to meters, divide it by 100: 7.5 cm / 100 = 0.075 m.

Finally, calculate the area of the input piston using the formula: A = π(0.075)^2.

b) The work done in lifting the car is given by the formula W = F × d, where W is the work, F is the force, and d is the distance over which the force is applied.

In this case, the force applied (F) is given as 160 N, and the distance (d) is given as 15 cm.

To convert the distance from centimeters to meters, divide it by 100: 15 cm / 100 = 0.15 m.

Now, use the formula to calculate the work done: W = 160 N × 0.15 m.

c) If the input piston moves 13 cm in each stroke, we need to find out how high the car moves up for each stroke.

Since the input piston moves 13 cm, the output piston also moves the same distance. Therefore, the distance the car moves up for each stroke is also 13 cm.

d) To calculate the number of strokes required to jack the car up 15 cm, divide the total distance to be covered (15 cm) by the distance covered in each stroke (13 cm).

So, the number of strokes required is 15 cm / 13 cm = 1.15 strokes. Since we can't have fractional strokes, we need to round up to the next whole number.

Therefore, it would take 2 strokes to jack the car up 15 cm.