Algebra
posted by Jim .
I need help solving this set of equations by substitution.
xy=2
3x − y + 5 = 0
I originally used (3x+5=y) and came up with (x=.333 and x=2) but when I substitute it into the original equation I get (y=2 and y=1) and it is wrong according to my homework. Please help me!

ok, go with y = 3x+5
into the 1st
x(3x+5) = 2
3x^2 + 5x  2 = 0
((3x1)(x+2) = 0
x = 1/3 or x = 2  > you are correct
if x = 1/3, y= 3(1/3) + 5 = 6
if x = 2 , y = 3(2) + 5 = 1
so x=1/3, y=6 OR x=2, y =1
I don't know how you got your values ???