algebra 2
posted by samantha godls .
Points R=(6,4), Q=(4,3), and P=(2,b) are collinear. What is the value of b?

the line through R and Q is
(y4)/(x6) = (34)/(46)
or
y = x/2 + 1
so, for (2,b) to be on the same line,
b = 2/2 + 1 = 0
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