math
posted by Britney .
Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.)
f(x)=x^3+3x^21 on [3,1]

math 
Steve
f(3) = 1
f(1) = 3
f'(x) = 3x^2 + 6x = 3x(x+2)
so, there are relative max/min at x= 2,0
f(2) = 3
f(0) = 1
So, on [3,1] we have
min = 1
max = 3
Respond to this Question
Similar Questions

Calculus (pleas help!!!)
Find the absolute maximum and absolute minimum values of the function f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals. Enter 1000 for any absolute extrema that does not exist. (A) Interval = [1,4] Absolute maximum … 
math
Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.) g(x)=x^2+4x+4 
Math
Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.) f(x)=x^3+3x^21 on [3,1] 
Math
Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.) f(x)=x^3+3x^21 on [3,1] 
math calculus
Find the absolute extrema of the function on the closed interval. Use a graphing utility to verify your results. (Round your answers to two decimal places. If an answer does not exist, enter DNE.) g(x) = (x^2 − 4)^2/3, [−5, … 
Calculus
Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.) f(x) = x^3 + 3 x^2  1 on [3, 1] 
Calculus
Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.) f(x) = −x2 + 2x + 3 on [3, 6] maximum minimum 
Calculus
Find the absolute maximum and absolute minimum values of the function f(x)=x^3+6x^263x+4 on each of the indicated variables. Enter DNE for does not exist. (A) Interval = [8,0] Absolute maximum = Absolute minimum = (B) Interval = … 
calculus
Find the absolute extrema of the function (if any exist) on each interval. (If an answer does not exist, enter DNE.) f(x) = square root of (25 − x^2) (a) [−5, 5] minimum (x, y) = (smaller xvalue) (x, y) = (larger xvalue) … 
calculus
Find the absolute extrema of the function (if any exist) on each interval. (If an answer does not exist, enter DNE.) f(x) = square root of (25 − x^2) (a) [−5, 5] minimum (x, y) = (smaller xvalue) (x, y) = (larger xvalue) …