# math

posted by .

Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.)

f(x)=x^3+3x^2-1 on [-3,1]

• math -

f(-3) = -1
f(1) = 3

f'(x) = 3x^2 + 6x = 3x(x+2)
so, there are relative max/min at x= -2,0

f(-2) = 3
f(0) = -1

So, on [-3,1] we have
min = -1
max = 3

## Similar Questions

1. ### Calculus (pleas help!!!)

Find the absolute maximum and absolute minimum values of the function f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals. Enter -1000 for any absolute extrema that does not exist. (A) Interval = [1,4] Absolute maximum …
2. ### math

Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.) g(x)=-x^2+4x+4
3. ### Math

Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.) f(x)=x^3+3x^2-1 on [-3,1]
4. ### Math

Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.) f(x)=x^3+3x^2-1 on [-3,1]
5. ### math calculus

Find the absolute extrema of the function on the closed interval. Use a graphing utility to verify your results. (Round your answers to two decimal places. If an answer does not exist, enter DNE.) g(x) = (x^2 − 4)^2/3, [−5, …
6. ### Calculus

Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.) f(x) = x^3 + 3 x^2 - 1 on [-3, 1]
7. ### Calculus

Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.) f(x) = −x2 + 2x + 3 on [3, 6] maximum minimum
8. ### Calculus

Find the absolute maximum and absolute minimum values of the function f(x)=x^3+6x^2-63x+4 on each of the indicated variables. Enter DNE for does not exist. (A) Interval = [-8,0] Absolute maximum = Absolute minimum = (B) Interval = …
9. ### calculus

Find the absolute extrema of the function (if any exist) on each interval. (If an answer does not exist, enter DNE.) f(x) = square root of (25 − x^2) (a) [−5, 5] minimum (x, y) = (smaller x-value) (x, y) = (larger x-value) …
10. ### calculus

Find the absolute extrema of the function (if any exist) on each interval. (If an answer does not exist, enter DNE.) f(x) = square root of (25 − x^2) (a) [−5, 5] minimum (x, y) = (smaller x-value) (x, y) = (larger x-value) …

More Similar Questions