Chemistry
posted by Deb .
y=2.12x + 0.004 and Protein A treated w/Bradford Reagent and has an A595 of 0.53. Can you please explain how to calculate this problem so I know in the future? Thanks for your help.
Respond to this Question
Similar Questions

Chemistry
If 12.50 grams of Pb(NO3)2 are reacted with 3.18 grams Nacl in a "typical double displacement" reaction, please calculate the following: a) What is the limiting reagent? 
CHEMISTRY
CALCULATE THE MASS OF Na3PO3 PRODUCED AFTER 28.0g OF H3PO3 IS TREATED WITH 42.0g OF NaOH, AND ALSO CALCULATE THE MASS REMAINING OF THE EXCESS REAGENT. H3PO3+ 3NaOH = Na3PO3+ 3H2O 
Chemistry
y=2.12x + 0.004 and Protein A treated w/Bradford Reagent and has an A595 of 0.53. Can you please explain how to calculate this problem so I know in the future? 
Algebra/Biology
y=2.12x + 0.004 and Protein A treated w/Bradford Reagent and has an A595 of 0.53. Can you please explain how to calculate this problem so I know in the future? 
chemistry
Expressing concentration in units of μg/mL or mg/mL are common in biochemistry, where accurate molecular weights of biomolecules are not always known. The plot below is the standard curve of a Bradford assay, a colorimetric method … 
Biochemistry
Can someone help me calculate protein concentration using the Bradford Assay? 
Chemistry
PLEASE HELP. If I have 0.10 mL of 200 mcg/mL protein, 0.90 mL of distilled water, and 2.00 mL of Bradford reagent, what is the concentration of the protein? 
Biuret & Lowry Method
Hello I want to ask several questions about Lowry and Biuret method. 1. Lowry Reagent C are prepared freshly. Why? 
Biology, Chemistry
I know how to carry out an absorption spectrum I just need help on how to to prepare my test tubes and what to put in then. I am very confused and any help would be greatly appreciated. THANKS ! You will be given a sample containing … 
Chemistry
I got 1.11 x 10^6 for K. Here is my work: x= 0.004 2x= 0.008 (change for CH4) Equilibrium for CH4 is 0.087  0.008= 0.079 Change in eq for C2H2 is 0.004 and eq is 0.004 (=x) Change in eq for H2 is 0.012 Eq for H2 is 0.012 K= [C2H2][H2]^3/[CH4]^2 …