posted by Anonymous

Find the dy/dx of the equation y=e^-x^2

  1. Steve

    equations do not have derivatives; functions do.

    for tis, use the chain rule: (e^u)' = e^u u'

    y = e^(-x^2)
    y' = e^(-x^2) (-2x) = -2x e^(-x^2)

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