what is the solution
1/2x^2-x+5=0
could someone please explain
just took the quiz
1. D ( 2i sqrt7 )
2. Graph B (imaginary : 2, Real : 4)
3. B ( 11-2i )
4. C ( 20-4i )
5. A ( 31+i / 26)
6. C ( 1 +/- i sqrt 9 )
I think you will find that if you mean
1/(2x^2-x+5)=0
there is no solution. The graph has a horizontal asymptote at y=0, meaning it never is really 0.
If that's not what you intended, then please clarify.
the possible answers are;
1+-i sqrt 11
-1+-i sqrt 9
1 +- i sqrt 9
-1 +- i sqrt 11
i figured it out to be 1+isqrt9
1. D 2isqrt7
2. B over 4 up 2
3. B 11-2i
4. C 20-4i
5. A 31+i/26
6. B 1+isqrt9
You're welcome
To find the solution of the given quadratic equation 1/2x^2 - x + 5 = 0, you can use the quadratic formula or try factoring or completing the square. Let's solve it using the quadratic formula.
The quadratic formula states that for any quadratic equation of the form ax^2 + bx + c = 0, the solutions can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
Now, let's identify the coefficients a, b, and c from the given equation:
a = 1/2
b = -1
c = 5
Plugging these values into the quadratic formula, we can calculate the solutions:
x = [-( -1) ± √((-1)^2 - 4(1/2)(5))] / (2(1/2))
Simplifying further, we get:
x = (1 ± √(1 - 4(1/2)(5))) / 1
x = (1 ± √(1 - 10)) / 1
x = (1 ± √(-9)) / 1
Notice that we have a negative value inside the square root. This means that solutions will be complex numbers. Simplifying further:
x = (1 ± √(-1 * 3^2)) / 1
x = (1 ± 3i) / 1
So, the solutions to the given equation are:
x = 1 + 3i
x = 1 - 3i
Therefore, the solutions to the equation 1/2x^2 - x + 5 = 0 are x = 1 + 3i and x = 1 - 3i.