There are 6 red marbles, 8 blue marbles, and 11 green marbles in a bag. What is the probability that you will randomly draw either a red or a blue marble?

24%
56%
32%
10%

nothing helped

To find the probability of randomly drawing either a red or a blue marble, we need to calculate the ratio of the favorable outcomes (number of red and blue marbles) to the total number of possible outcomes (total number of marbles in the bag).

The number of red marbles is 6 and the number of blue marbles is 8. Therefore, the total number of favorable outcomes is 6 + 8 = 14.

The total number of marbles in the bag is the sum of the red, blue, and green marbles, which is 6 + 8 + 11 = 25.

To calculate the probability, we divide the number of favorable outcomes by the total number of possible outcomes:

Probability = (Number of favorable outcomes) / (Total number of possible outcomes)

Probability = 14 / 25 ≈ 0.56

Therefore, the probability of randomly drawing either a red or a blue marble is approximately 0.56 or 56%.

Either-or probability is found by adding the individual probabilities.

6/25 + 8/25 = ?