college algebra

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For the given equation list the intercepts.
Y= -2X/(X^2+1)
I think I Have this right I am not for sure?

y=-2x/(x^2+1)
(0)=(-2x/x^2+1)
-2x/x^2+1=0
-2/x+1=0
-2/x+1+0
-2/x*x+1*x=0*x
-2+x=0
x=2

y-intercept
y= -2*0/(0)^2+1
y=o/0^2+1
y=0+1
y=0/0+1

x-intercept:(2,0)
y-intercept:(0,0)

  • college algebra -

    no , from your lines

    -2x/x^2+1=0
    -2/x+1=0
    at the start you had (x^2 +1) in brackets as I just did
    so when you divide top and bottom by x, every term has to be divided by x
    and you would get
    -2/(x + 1/x) = 0

    but I would not do that
    If a fraction = 0 , then the zero can only come from the numerator, and the denominator could never be zero, or else we would be dividing by zero

    so in
    -2x/(x^2+1) = 0
    -2x = 0
    x = 0
    so (0,0) is both an x and a y intercept.

  • college algebra -

    ok thanks

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