algebra 1
posted by Janet .
Solve the following system of linear equation using any algebraic method.
2x+5y=3
X3y=7

from the 2nd:
x3y = 7 > x = 3y+7
sub into the first
2x + 5y = 3
2(3y+7) + 5y = 3
6y + 14 + 5y = 3
11y = 11
y = 1
sub that into x = 3y+7 = 3+7 = 4
x = 4 , y = 1
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