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A 5.00-g bullet is fired into a 500-g block of wood suspended as a ballistic pendulum.
The combined mass swings up to a height of 10.00 cm. What was the magnitude of the
momentum of the combined mass immediately after the collision?
The Ans is 0.707 kg m/sec
I do not know how to go get this answer


    Energy is conserved during the upward swing. Therefore
    (M+m)V = (M+m)gH
    V = gH = 0.98 m/s
    is the block velocity just after the bullet (mass m) is embedded inside the block (mass M). The momentum at that time is
    (M+m)V = (0.505 kg)*V = 0.495 kg m/s

    I do not agree with the 0.707 answer.

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