college physics
posted by Gee .
A ball is thrown from a 20.0m high building and hits the ground 6.0m from the building. With what horizontal velocity was it thrown?

h = ho  (Vo*t + 0.5g*t^2) = 0.
20  (0 + 4.9t^2) = 0
20  4.9t^2 = 0
4.9t^2 = 20
t^2 = 4.08
Tf = 2.02 s. = Fall time.
Range = Xo * Tf = 6 m.
Xo*2.02 = 6
Xo = 2.97 m/s. = Initial hor. velocity.
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