algebra
posted by jayson .
What is the equation in standard form of a parabola that models the values in the table?
x 2 0 4
f(x) 1 5 59

This is what I have so far if someone could help me finish.
a(2)^2+b(2)+c=1
a(0)^2+b(0)+c=5
a(4)^2+b(4)+c=59
4a2b+c=1
0a+0b+c=5 c=5
16a+4b+c=59
4a2b+5=1
16a+4b+5=59
4a2b+55=15
4a2b=4
16a+4b+55=595
16a+4b=64
Now I'm not sure if I'm doing this right.
4(4a2b)=4*4
16a+4b=16
16a8b=16
16a+4b=64
16a8b(16a+4b)=36(64)
I'm lost!
Can someone please help?