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a firecracker is fired from the ground. The height of the firecracker at a given time is modeled by the function h(t) =-5t^2+50t, where h(t) is the height in metres and t is the time in seconds. When will the firecracker reach a height of 45m ?

  • Math -

    solve for t in

    45 = -5t^2 + 50t
    5t^2 - 50t + 45 = 0
    t^2 - 10t + 9 = 0
    (t-9)(t-1) = 0

    it will reach 45m on the way up at t=1, and on the way back down at t=9.

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