math
posted by danica .
the perimeter of a rectangle is 160m and its area is 1200m^2 find its dimensions

I'll get you started.
√ 1200 = 34.64 
then what i seriously have no clue what im doing

With a little trial and error, I found that the dimensions must be 20 by 60

2w + 2l = 160
w+l = 80
l= 80w
wl = 1200
w(80w) = 1200
80w  w^2  1200=0
w^2  80w + 1200 = 0
(w20)(w  60) = 0
w = 20 or w = 60
if w = 20, then l = 8020 = 60
and if w  60 , then l = 8060 = 20
So the rectangle is 20 by 60 as Ms Sue found by trialanderror
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