# geometery

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1.given the function y=x^2-4x+5,find the following:
a.vertex
b.maximum or minimum
c.axis of symmetry
d.y-intercept
e.x-intercept(zeros)
f.graph

• geometery -

complete the square ....

y = x^2 - 4x + 4 - 4 + 5
= (x-2)^2 + 1

vertex is (2,1)
opens up, so minimum
axis of symmetry: x = 2
y-intercepts: let x = 0, y = 5
x-intercepts:
let y = 0
x^2 - 4x+ 5 = 0
(x-5)(x+1) = 0
x = 5, x = -1 , notice the x of the vertex is midway between these.

graph: you do it.

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