geometery
posted by sophie .
1.given the function y=x^24x+5,find the following:
a.vertex
b.maximum or minimum
c.axis of symmetry
d.yintercept
e.xintercept(zeros)
f.graph

complete the square ....
y = x^2  4x + 4  4 + 5
= (x2)^2 + 1
vertex is (2,1)
opens up, so minimum
axis of symmetry: x = 2
yintercepts: let x = 0, y = 5
xintercepts:
let y = 0
x^2  4x+ 5 = 0
(x5)(x+1) = 0
x = 5, x = 1 , notice the x of the vertex is midway between these.
graph: you do it.