what is the smallest number which must be subtracted from 208 to leave a number which is exactly divisible by7?
208 - 5 = 203
203 / 7 = 29
Good
To find the smallest number that must be subtracted from 208 to leave a number that is exactly divisible by 7, we need to find the remainder when 208 is divided by 7.
The remainder can be found by taking the modulus of 208 divided by 7:
208 % 7 = 6
Since the remainder is 6, we need to subtract 6 from 208 in order to obtain a number exactly divisible by 7.
Therefore, the smallest number that must be subtracted from 208 is 6.
To find the smallest number that must be subtracted from 208 to leave a number that is exactly divisible by 7, you can follow these steps:
1. Identify the remainder: Divide 208 by 7 to find the remainder. In this case, 208 รท 7 = 29 with a remainder of 5.
2. Determine the number to subtract: Since the remainder is 5, subtracting 5 from 208 will give you a number that is divisible by 7.
Therefore, the smallest number that must be subtracted from 208 to leave a number that is exactly divisible by 7 is 5.