Post a New Question


posted by .

how many milliliters of 0.250 M KMnO4 are needed to react with 3.55 grams of iron(II)sulfate, FeSO4? the reaction is as follows:

  • chemistry -

    mols FeSO4 = grams/molar mass = ?
    Use the coefficients in the balanced equation to convert mols FeSO4 to mols KMnO4.
    M KMnO4 = mols KMnO4/L KMnO4. You know M and mols, solve for L and convert to mL.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question