Is this equation correctly balanced? If not why.
Al2S3+H2O---->
Al2S3+3H2O---->Al2(SO)3+3H2
No.
1. I am not aware of anything with the formula Al2(SO)3--I don't think this exists.
2. It doesn't form H2 gas.
3. If you need some help, Al2S3 hydrolyzes easily to form Al(OH)3 + H2S as the products.
To determine if the equation is correctly balanced, we need to check if both sides of the equation have an equal number of each element.
Let's count the atoms on each side of the equation:
On the left-hand side:
- Al: 2 atoms
- S: 3 atoms
- H: 2 atoms
- O: 0 atoms
On the right-hand side:
- Al: 2 atoms
- S: 1 atom
- O: 3 atoms
- H: 6 atoms
Since the number of atoms is not the same on both sides of the equation, we can conclude that the equation is not correctly balanced.
To balance the equation, we need to adjust the coefficients in front of the molecules and atoms.
Starting with Al, we have 2 atoms on the left and 2 atoms on the right, so Al is already balanced.
Next, let's balance S. We have 3 atoms on the left and 1 atom on the right. To balance it, we need to put a coefficient of 3 in front of Al2(SO)3.
Now, let's balance O. We have 3 atoms on the right and 0 atoms on the left. To balance it, we need to put a coefficient of 3 in front of H2O on the left side.
Finally, let's balance H. We have 2 atoms on the left and 6 atoms on the right. To balance it, we need to put a coefficient of 3 in front of H2 on the left side.
The correctly balanced equation is:
Al2S3 + 3H2O ----> Al2(SO)3 + 3H2