Post a New Question

math

posted by .

the perimeter of a dog park is 156 ft. If the length of the park is 2 ft. less than 3 times the width, what are the dimensions of the dog park?

  • math -

    width ---- w
    length ---- 3w - 2

    2w + 2(3w-2) = 156
    2w + 6w - 4 = 156
    8w = 160
    w = 20

    park is 20 by 58

  • math -

    The dimensions of the dog part are 20ft by 56 ft.

    Set up the problem

    w + w + ( 3w - 2 ) + ( 3w - 2 ) = 156

  • math -

    P = 2L + 2W

    156 = 2(3W - 2) + 2W

    156 = 6W - 4 + 2W

    160 = 8W

    20 = W

    ~~~~~~~~~~~~~~~~`

    L = 58

  • math -

    sorry I post 56 instead of 58, the dimensions are 20ft by 58ft

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question