# math

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the perimeter of a dog park is 156 ft. If the length of the park is 2 ft. less than 3 times the width, what are the dimensions of the dog park?

• math -

width ---- w
length ---- 3w - 2

2w + 2(3w-2) = 156
2w + 6w - 4 = 156
8w = 160
w = 20

park is 20 by 58

• math -

The dimensions of the dog part are 20ft by 56 ft.

Set up the problem

w + w + ( 3w - 2 ) + ( 3w - 2 ) = 156

• math -

P = 2L + 2W

156 = 2(3W - 2) + 2W

156 = 6W - 4 + 2W

160 = 8W

20 = W

~~~~~~~~~~~~~~~~`

L = 58

• math -

sorry I post 56 instead of 58, the dimensions are 20ft by 58ft

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