Post a New Question


posted by .

A block of mass 0.86 kg is suspended by a string which is wrapped so that it is at a radius of 0.061 m from the center of a pulley. The moment of inertia of the pulley is 4.60×10-3 kg·m2. There is friction as the pulley turns. The block starts from rest, and its speed after it has traveled downwards a distance of D= 0.73 m, is 1.939 m/s. Calculate the amount of energy dissipated up to that point.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question