posted by Shelby .
Two moles of Mg and five moles of O2 are placed in a reaction vessel, and then the Mg is ignited to produce Mg (F.W.= 40.31 g/mole). What is the actual mole ratio, the calculated mole ratio, how many moles of MgO are formed, and what is the weight of MgO formed?
You made a typo; I'm sure you wanted that to read....."the Mg is ignited to produce MgO."
The answers are
2Mg + O2 ==> 2MgO
Two mols Mg will produce two mols MgO (in an excess of oxygen).
It appears the other questions relate to an experiment conducted with Mg and O2; therefore, you are to substitute the value you found in the experiment.
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