Post a New Question

College Physics

posted by .

A uniform horizontal rod of mass M and length l rotates with angular velocity w (omega) about a vertical axis through its center. Attached to each end of the rod is a small mass m. Determine the angular momentum of the system about the axis. Write you're answer in terms of M, m, l and w (omega).

  • College Physics -

    The moment of inertia of the rod with the two masses at each end is:

    I = M*L^2/12 + 2*m*(L/2)^2
    = M*L^2/12 + m*L^2/2
    = (M + 6m)*L^2/12
    The angular momentum is
    I*w = (M+6m)*w*L^2/12.

  • College Physics -

    If Wire A has a poterntial difference of 50V across it and carries a current of 2A. Wire B has a potential difference of 100V across it and also carries a current of 2A. Compare the resistances, rate of flow of charge, and rate of flow of energy in the two wires?

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question