What is the energy of a photon corresponding to radio waves of frequency 1.465 106 /s?
To find the energy of a photon corresponding to a specific frequency, you can use the formula:
E = h * f
Where:
E is the energy of the photon,
h is the Planck's constant (h = 6.626 x 10^-34 J*s),
f is the frequency of the electromagnetic wave.
In this case, the frequency is given as 1.465 x 10^6 /s.
Let's substitute the values into the formula:
E = (6.626 x 10^-34 J*s) * (1.465 x 10^6 /s)
Now, calculate the product:
E = 9.687 x 10^-28 J
So, the energy of a photon corresponding to radio waves with a frequency of 1.465 x 10^6 /s is approximately 9.687 x 10^-28 J.
To find the energy of a photon corresponding to radio waves of a given frequency, you can use the equation:
E = h * f
where E is the energy of the photon, h is Planck's constant (approximately 6.626 x 10^-34 J·s), and f is the frequency of the radio waves.
In this case, the frequency is given as 1.465 x 10^6 /s. Substituting this value into the equation, we get:
E = (6.626 x 10^-34 J·s) * (1.465 x 10^6 /s)
Now, multiply the numbers and simplify the units:
E = 9.695 x 10^-28 J
Therefore, the energy of a photon corresponding to radio waves with a frequency of 1.465 x 10^6 /s is approximately 9.695 x 10^-28 joules (J).